Leetcode / 2433. Find The Original Array of Prefix Xor
Pick a programming language:
Here is the source code for the solution to this problem.
class Solution {
public int[] findArray(int[] pref) {
int[] arr = new int[pref.length];
arr[0] = pref[0];
for (int i = 1; i < pref.length; i++) {
// the previous element already computes the XOR up to i - 1.
// If you have pref[i] = arr[0] XOR arr[1] ... XOR arr[i]
// then you can do pref[i] = (pref[i - 1]) XOR arr[i]
// The XOR operation of a = b XOR c can also be written as c = b XOR a:
arr[i] = pref[i - 1] ^ pref[i];
}
return arr;
}
}
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